Math, asked by Mayank7771, 1 year ago

find the value of sin 60 and sec 30 geometrically

Answers

Answered by vinay140
2

 sin(60 )   =   \sqrt{3  \div 2 }
 \sec(30)  = 2 \div  \sqrt{3}


Answered by prince53147
0

Answer:

sin 60 =√3/2

cos 30= √3/2

hope helpful to you

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