find the value of sin 60 geometrically?
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the value of 60 geometreically in trignometry is root 3 by 2
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Answer:
√3/2
Step-by-step explanation:
step 1: draw a equilateral triangle (all sides equal) and name ABC.
step 2: drop a altitude from ∠A to BC at D.
step 3: BD = DC = a (altitude of a equilateral triangle bisects the side).
step 3: In ∆ABD,
∠B = 60°
AB = 2a
BD = a
By Pythagoras theorem,
AD = a√3
sin θ = opposite side/hypotenuse
sin B = a√3/2a
sin 60° = √3/2
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