find the value of sin 60 geometrically
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Sin 60 is equal to
Root3/2
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Answer:
Step-by-step explanation:
Construction an equilateral triangle ABC . Drop a perpendicular from a to BC . Name it as D.
Now AD is the median as well as an altitude.
Therefore BD = DC
Let AB = 2a
BD=1/2BC
Or BD= 1/2 AB
I.e BD = a
Now in triangle ABD,
AB^2=AD^2 + BD^2
Or (2a)^2= AD^2 + a^2
4a^2-a^2= AD^2
AD^2=3a^2
AD=√3a
Sin 60°= P/H = √3a/2a = √3/2
Hence proved
parminder256:
thanks this answer helped me alot
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