Find the value of sin 60°+cos 30°- tan 30°
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√3/2 +√3/2 -1/√3
=√3- 1/√3 = (√3²-1)/√3 =2/√3
= 2√3/3
=√3- 1/√3 = (√3²-1)/√3 =2/√3
= 2√3/3
rohitdivekar46:
2 AtA hai
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Sin 60=√3/2
Cos30=√3/2
Tan 30=1/√3
Substitute the values
N get the and as 2
Cos30=√3/2
Tan 30=1/√3
Substitute the values
N get the and as 2
Multiple throughout by √3 n then take LCM
Plz like if it's right
N correct me if I'm wrong feel free to coment
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