Question

find the value of sin 60°/cos² 45° - cot 30°+5cos 90°​

Answer 1

Answer:

We have,

$\frac{sin60 }{ {cos}^{2}45 } = - cot \: 30 \: + 15cos90∘ \: = \frac{ {2}^{ | \sqrt{3} | } }{(1 \sqrt{2} ^{2} ) } </p><p></p><p></p><p></p><p></p><p></p><p>$

$</p><p>3+15×0=3−3+0=0</p><p></p><p>$

Answer 2

Answer:-

Explain:-

Sin60°=√3/2

cos45°=1

Cot30°=√3

cos90°=0

=>sin60°/cos²45°-cot30°+5cos 90°

=>√3/2/1²-√3+5×0

=>√3/2-√3/0

=>√3/2-0=√3/2