Math, asked by khandlanaranbhai, 28 days ago

find the value of sin 60°+cosec60°​

Answers

Answered by Anonymous
1

sin60 + cosec 60

 \frac{ \sqrt{3} }{2}  +   \frac{2}{ \sqrt{3} }  \\   = \frac{3 + 4}{2 \sqrt{3} }  \\  =  \frac{7}{2 \sqrt{3} }

Answered by rakshitasethi
0

Step-by-step explanation:

sin60= root3/2

cosec60= 1/ sin60 = 2/ root 3

thus,

 \frac{ \sqrt{3} }{2}  +  \frac{2}{ \sqrt{3} }  =  \frac{7}{2 \sqrt{3} }

hope It helps

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