Question

find the value of sin ( 690°)​

Answer 1

Answer:

sin690∘=sin(720∘−30∘) , =sin(4π−π6) . But, sin(4π−θ)=−sinθ . ∴sin690∘=−sin30∘=−12

Answer 2

Solution:-

The exact value of sin690°= -0.912920646