Find the value of sin 75°
shanamsudhar2222:
clear i will tell easier
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sin ( A+B ) = sin A * cos B + cos A * sin B
sin ( 30+45 ) = sin 30 cos 45 + cos 30 * sin 45
sin 75 = (1/2)*(1/√2) + (√3/2)*(1/√2)
sin 75 =( 1/2√2 )+ (√3/2√2)
sin 75 = (1+√3)/2√2
sin ( 30+45 ) = sin 30 cos 45 + cos 30 * sin 45
sin 75 = (1/2)*(1/√2) + (√3/2)*(1/√2)
sin 75 =( 1/2√2 )+ (√3/2√2)
sin 75 = (1+√3)/2√2
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