Math, asked by Anonymous, 10 months ago

Find the value of sin 750 cos 300° + cos 1470" sin (-1020)

Answers

Answered by amitnrw

Step-by-step explanation:

sin 750° cos 300° + cos 1470°sin (-1020°)

= sin(720° + 30°) Cos(360° - 60°) + Cos(1440° + 30°)(-Sin(1020°)

Sin( n * 360 + x) = Sinx Sin( n * 360 - x) = -Sinx

Cos( n * 360 + x) = Cosx Cos( n * 360 - x) = Cosx

Sin(-x) = -Sinx

= sin(2*360°° + 30°)Cos(360° - 60°) + Cos(4*360° + 30°)(-Sin(1080° - 60°)

= Sin30° Cos 60° + Cos30 Sin60

Sin(A + B) = SinACosB + CosASinB

= Sin(30° + 60°)

= Sin90°

= 1

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Answered by dhakatanishqddun

Answer:

The answer is 1.

Step-by-step explanation:

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