Math, asked by ssassociate397, 2 months ago

Find the value of sin 75° cos15°+cos 75°sin 15°


guys pls help me with this​

Answers

Answered by Anonymous
1

√3/2

Step-by-step explanation:

sin 75° cos 15°+cos 75°sin 15°

sin(75°+15°). {sin(A+B)= sinAcosB + cosAsinB}

sin(90°)

sin90°

 =  \frac{ \sqrt{3} }{2}

Answered by 203114inbatamilan
1

Answer:

1

explanation:

sin 75° cos15°+cos 75°sin 15°

 sina cosb + sinb cosa \:  =  \sin(a + b)

sin 75° cos15°+cos 75°sin 15°=sin(75°+15°)

=sin90°

=1

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