Question

Find the value of sin 76ºcos 16°- cos 76°sin 16°​

Answer 1

Answer:

Sin76°cos16°- cos76°sin16°

=sin76°sin(90°-16°)-cos76°cos(90°-16°). [ Sin a=cos(90°-a)]

=sin76°sin76°-cos76°cos76°

=sin^2 76°- cos^2 76°

=(sin76°+cos76°)(sin76°-cos76°)

Hope it helps

if the sine in middle was + then

Sin^2 76° + cos^2 76°= 1. [ Sin^2 A +cos^2 A=1]