Question

find the value of sin 90 degrees + cos 30 degrees minus tan 45 degrees + Cos 60 degrees + cot 90 degrees​

Answer 1

I hope that this answer helps you

Answer 2

The value of the provided expression is $\frac{1+\sqrt{3}}{2}$.

Step-by-step explanation:

Consider the provided information

$\sin \left(90^{\circ \:}\right)+\cos \left(30^{\circ \:}\right)-\tan \left(45^{\circ \:}\right)+\cos \left(60^{\circ \:}\right)+\cot \left(90^{\circ \:}\right)$

Use the trivial identity:

$\sin \left(90^{\circ \:}\right)=1, \cos \left(30^{\circ \:}\right)=\frac{\sqrt{3}}{2}, \tan \left(45^{\circ \:}\right)=1, \cos \left(60^{\circ \:}\right)=\frac{1}{2}, \cot \left(90^{\circ \:}\right)=0$

Substitute the respective values.

$=1+\frac{\sqrt{3}}{2}-1+\frac{1}{2}+0$

$=\frac{1}{2}+\frac{\sqrt{3}}{2}$

$=\frac{1+\sqrt{3}}{2}$

Hence, the value of the provided expression is $\frac{1+\sqrt{3}}{2}$.

#Learn more

Find the value of sin square 60 degree + cos square 30 degree - tan square 45 degree by cot square 30 degree

https://brainly.in/question/9894355