Question

find the value of sin 90-sin 60​

Answer 1

Sin90 =1 and sin60=(sqrt 3)/2
So sin90-sin60= 1-(sqrt3)/2=(2-sqrt3)/2

Answer 2

Answer:

$\sin(90) - \sin(60) \\ 1 - \frac{ \sqrt{3} }{2} ........putting \: the \: values \: from \: trigonometry \: table \\ \frac{2 - \sqrt{3} }{2} \\ therefore \: \sin(90) - \sin(60) = \frac{2 - \sqrt{3} }{2}$

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