find the value of sin(a+b)when tan (a+b) =√3
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tan ( a + b ) = root 3
But,
tan 60 = root 3.
So,
tan (a+b) = tan 60
So, a+b = 60
By putting the value of a+b,
sin (a+b) = sin 60
So, sin (a+b) = root 3 ÷ 2
But,
tan 60 = root 3.
So,
tan (a+b) = tan 60
So, a+b = 60
By putting the value of a+b,
sin (a+b) = sin 60
So, sin (a+b) = root 3 ÷ 2
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