Question

Find the value of (sin A + cos A)²– 2 sin A cos A.

Answer 1

To find the value of,

(sinA + cosA)² -2sinAcosA

★Expanding the given expression,

sin²A + cos²A +2sinAcosA -2sinAcosA

=sin²A + cos²A

We know that,

sin²∅+cos²∅=1

Thus,

sin²A + cos²A = 1

The answer of given expression is 1

Answer 2

I think the answer is sinA

${sina }^{2} + {cosa}^{2}$