Question

Find the value of (sin θ + cos θ) ²+ (cos θ -sin θ) ²

Answer 1

☛ ( sin θ + cos θ )² + (cos θ - sin θ)²

☛ sin² θ + cos² θ + 2sinθcosθ + sin²θ + cos²θ - 2cosθsinθ

☛ 1 + 2sinθcosθ + 1 - 2sinθcosθ

☛ 1 + 1

☛ 2

Formulae Used:

➜ (a + b)² = a² + b² + 2ab

➜ (a - b)² = a² + b² - 2ab

➜ sin² θ + cos² θ = 1

Answer 2

Answer:

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Step-by-step explanation:

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