Find the value of sin(cot^-1 x)
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Answered by
0
Answer:
sin(cot^-1x)
sin(cosx/sinx)
cancel sinx and answer will be cosx
Answered by
0
Good morning dear
Here is your answer
Let cot
−1
x=θ
cotθ=x
sinθ
cosθ
=x
sin
2
θ
cos
2
θ
=x
2
(1−sin
2
θ)=x
2
sin
2
θ
sin
2
θ=
1+x
2
1
sinθ=
1+x
2
±1
sinθ=
1+x
2
1
or sinθ=−
1+x
2
1
∴sin(cot
−1
x)=(1+x
2
)
−
2
1
or sin(cot
−1
x)=−(1+x
2
)
−
2
1
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