find the value of sin inverse
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Pls check the link in the dsecription
https://brainly.in/question/5767710
or
pls check the a below
The value of sin^(-1) ( sin 3π/5 ) is supposed to be equal to 3π/5
But actually it's not!
For sin^(-1) ( sin x ) , x must be within [-π/2, π/2]
Clearly 3π/5 > π/2
So,
sin^(-1) ( sin 3π/5 ) = sin^(-1) ( sin (π - 3π/5 )) = sin^(-1) ( sin 2π/5 ) = 2π/5 ∈ [-π/2, π/2]
The answer is 2π/5
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Step-by-step explanation:
I an week in trigonometry
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