Question

find the value of sin ø cos(90-ø) + cos ø sin(90-ø).

Answer 1

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Here is Your Answer...!!!
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↪⭐ Actually welcome to the concept of the TRIGONOMETRIC IDENTITY

⭐↪Since we apply here

↪Sin ( A+B) = sinA cosB + CosA sinB

↪so we get as ....

↪Sin ( 90 + ⊙ - ⊙ )

↪that is Sin 90° = 1

Answer 2

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HERE'S THE ANSWER ✌

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QUESTION:find the value of sin ø cos(90-ø) + cos ø sin(90-ø).

$let \: the \: angle \: be \: \alpha$
$\sin( \alpha ) \cos(90 - \alpha) + \cos( \alpha ) \sin(90 - \alpha )$

from identity,

cos (90° -θ) = sin θ
sin (90° - θ) = cos θ 

it will become

$(\sin\alpha) ({ \sin \alpha }) + (\cos \alpha ) ( \cos\alpha )$
$({ \sin \alpha ) }^{2} + ( { \cos \alpha ) }^{2}$
= 1.... answer

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