Question

Find the value of sin[sin^-1(3/5)+cos^-1(3/5)]​

Answer 1

Answer:

1

Step-by-step explanation:

sin[tan∧-1(3/4)+tan∧-1(4/3)]

=sin[tan^-1(3/4)+cot^-1(3/4)]

=sin(pi/2)

=sin90

=1

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