find the value of (sin sq. theta
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Step-by-step explanation:
Consider a Right Angled Triangle ΔABC , right angled at B:
sinθ is defined to be the ratio of perpendicular (AB) to hypotonous (AC)⟹sinθ=ABAC Eqn(1)
cosθ is defined to be the ratio of base (BC) to hypotonous (AC)⟹cosθ=BCAC Eqn(2)
But, According to Pythagoras Theorem: (AB)2+(BC)2=(AC)2
Now, on Dividing both the sides by (AC)²:
⟹AB2AC2+BC2AC2=1
Now, on Substituting values From Eqn(1) and Eqn(2):
⟹sin2θ+cos2θ=1
Hence proved: sin2θ+cos2θ=1
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