Find the value of sin square 22 degree + sin square 68 degree divided by cos square 22 degree + cos square 16 degree + sin square 63 degree + cos 63 degrees sin 27 degrees
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Answered by
111
[sin^2 22+ sin ^2 (90-68)/cos^2 68+cos^2sin. (90-22) ] + sin^2 (63)+cos63xsin27..
(1/1) +sin^2 (63)+ cos63x sin(90-63)
(1/1) +sin^2(63) + cos63xcos63
(1/1) +sin^2(63) +cos^2(63)
(1/1) + 1
2.
hope u understand the solution
(1/1) +sin^2 (63)+ cos63x sin(90-63)
(1/1) +sin^2(63) + cos63xcos63
(1/1) +sin^2(63) +cos^2(63)
(1/1) + 1
2.
hope u understand the solution
Answered by
53
Hope this helps uhh!!!
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