find the value of sin square 33 degrees + sec square 47 degree
Answers
Answer:
The perimeter of a rectangular garden is 196 m.
Length is 5m more than twice its breadth.
To Find :
Length and Breadth of Garden .
Solution :
\longmapsto\tt{Let\:Breadth\:be=x}⟼LetBreadthbe=x
As Given that Length is 5m more than twice its breadth. So ,
\longmapsto\tt{Length=2x+5}⟼Length=2x+5
Using Formula :
\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}⟼
PerimeterofRectangle=2(l+b)
Putting Values :
\longmapsto\tt{196=2(2x+5+x)}⟼196=2(2x+5+x)
\longmapsto\tt{\cancel\dfrac{196}{2}=3x+5}⟼
2
196
=3x+5
\longmapsto\tt{98-5=3x}⟼98−5=3x
\longmapsto\tt{93=3x}⟼93=3x
\longmapsto\tt{\cancel\dfrac{93}{3}=x}⟼
3
93
=x
\longmapsto\tt\bf{31=x}⟼31=x
Value of x is 31 .
Therefore :
\longmapsto\tt{Breadth\:of\:Garden=x}⟼BreadthofGarden=x
\longmapsto\tt\bf{31\:m}⟼31m
Answer:
this our answer 30 hope it helps you