Math, asked by hasinithumati, 1 month ago

find the value of sin square 33 degrees + sec square 47 degree​

Answers

Answered by utsavshakya49
0

Answer:

The perimeter of a rectangular garden is 196 m.

Length is 5m more than twice its breadth.

To Find :

Length and Breadth of Garden .

Solution :

\longmapsto\tt{Let\:Breadth\:be=x}⟼LetBreadthbe=x

As Given that Length is 5m more than twice its breadth. So ,

\longmapsto\tt{Length=2x+5}⟼Length=2x+5

Using Formula :

\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}⟼

PerimeterofRectangle=2(l+b)

Putting Values :

\longmapsto\tt{196=2(2x+5+x)}⟼196=2(2x+5+x)

\longmapsto\tt{\cancel\dfrac{196}{2}=3x+5}⟼

2

196

=3x+5

\longmapsto\tt{98-5=3x}⟼98−5=3x

\longmapsto\tt{93=3x}⟼93=3x

\longmapsto\tt{\cancel\dfrac{93}{3}=x}⟼

3

93

=x

\longmapsto\tt\bf{31=x}⟼31=x

Value of x is 31 .

Therefore :

\longmapsto\tt{Breadth\:of\:Garden=x}⟼BreadthofGarden=x

\longmapsto\tt\bf{31\:m}⟼31m

Answered by tivnkant
2

Answer:

this our answer 30 hope it helps you

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