Question

find the value of sin square 7 + sec square 23 + sin square 83 - cot
square 67​

Answer 1

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sin^2(7)+sec^2(23)+sin^2(83)-cot^2(67)

=sin^2(7)+cosec^2(90-23)+cos^2(90-83)-cot^2(67)

=(sin^2(7)+cos^2(7))+(cosec^2(67)-cot^2(67))

=1+(1+cot^2(67)-cot^2(67))

=1+(1)

=2