Question

Find the value of sin
$15find \: the \: value \: of \: sin (15|$
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Answer 1

Answer:

sin 15° = sin( 45 - 30)°

Now, use formula sin ( A - B ) = sinA cosB - cosA sinB

So, sin( 45 - 30)° = sin45° cos30° - sin30° cos45°

sin( 45 - 30)° = $\mathsf{\dfrac{\sqrt{3}}{2{\sqrt{2}}}} - {\dfrac{1}{2{\sqrt{2}}}}$

• sin( 45 - 30)° = $\mathsf{\dfrac{\sqrt{3} - 1}{2{\sqrt{2}}}}$