Question

find the value of sin theta + cos theta whole square + cos theta minus sin theta whole square​

Answer 1

Answer: 2

Step-by-step explanation:

Let the angle be x. Then,

Sin²x + cos²x +2sinx.cosx + cos²x + sin²x - 2sinx.cosx.

= 2(sin²x + cos²x) = 2× 1 = 2

Answer 2

Answer:

Step-by-step explanation: (Sin theta + cos theta )^2 + (cos theta - sin theta )^2

Sin ^2 theta + cos^2 + 2sintheta.costheta+cos^2theta+sin^2ttheta-2costheta.sintheta

{ Sin^2 theta + cos ^2 theta =1}

1+1=2