Question

Find the value of sin theta if 6 cos square theta = 4 1/2​

Answer 1

I want to know that 41/2 ???

Answer 2

The value is  $\sin\theta=\pm \frac{1}{2}$.

Step-by-step explanation:

Given : Expression  $6\cos^2\theta=4\frac{1}{2}$

To find : The value of $\sin \theta$ ?

Solution :

Re-write the expression as,

$6\cos^2\theta=\frac{9}{2}$

$\cos^2\theta=\frac{9}{2\times 6}$

$\cos^2\theta=\frac{3}{4}$

Using trigonometric formula,

$\sin^2\theta=1-\cos^2 \theta$

$\sin^2\theta=1-\frac{3}{4}$

$\sin^2\theta=\frac{4-3}{4}$

$\sin^2\theta=\frac{1}{4}$

Taking root both side,

$\sin\theta=\sqrt{\frac{1}{4}}$

$\sin\theta=\pm \frac{1}{2}$

Therefore, the value is  $\sin\theta=\pm \frac{1}{2}$.

#Learn more

Sin^theta - 1 / 2 sin theta = 0 . Find the value of theta

https://brainly.in/question/760266