Find the value of sin (+) without using table if sin = 3/5 and tan = 5/1 and and are acute
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Answer:
Step-by-step explanation:
Given, sinA=3/5 and A is an acute angle.
So, in ΔABC we have ∠B=90
0
,
And AC=5 and BC=3,
By Pythagoras theorem,
AB=
(AC
2
−BC
2
)
=
(5
2
−3
2
)
=
(25−9)
=
16
=4.
Now,
cosA=AB/AC=4/5
tanA=BC/AB=3/4
cotA=1/tanθ=4/3.
secA=1/cosθ=5/4.
cosecA = 1/sinθ=5/3
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