Find the value of sin(x/2),cos(x/2) and tan(x/2). if sinx=-1/2 in 3rd quadrant
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Answered by
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Hello!
Here is your answer
Given
Sin x lies in the third quadrant .
In the third quadrant of the graph the values of X and Y are negative.
Sin x = -1/2
Therefore the value of x is -30
(To know more about trigonometric ratios and values read the table)
¤ Sin (x/2) = Sin (-30/2) = Sin (-15) which is nearly equal to -0.6502.
¤ Cos (x/2) = Cos (-30/2) = Cos (-15) = Sin (-75) = -0.7596.
¤ Tan (x/2) = Tan (-30/2) = Tan (-15) = -0.6502/-0.7596 = 0.8559.(Tan = Sin/Cos).
Here is your answer
Given
Sin x lies in the third quadrant .
In the third quadrant of the graph the values of X and Y are negative.
Sin x = -1/2
Therefore the value of x is -30
(To know more about trigonometric ratios and values read the table)
¤ Sin (x/2) = Sin (-30/2) = Sin (-15) which is nearly equal to -0.6502.
¤ Cos (x/2) = Cos (-30/2) = Cos (-15) = Sin (-75) = -0.7596.
¤ Tan (x/2) = Tan (-30/2) = Tan (-15) = -0.6502/-0.7596 = 0.8559.(Tan = Sin/Cos).
Answered by
0
Hello!
Here is your answer
Given
Sin x lies in the third quadrant .
In the third quadrant of the graph the values of X and Y are negative.
Sin x = -1/2
Therefore the value of x is -30
(To know more about trigonometric ratios and values read the table)
¤ Sin (x/2) = Sin (-30/2) = Sin (-15) which is nearly equal to -0.6502.
¤ Cos (x/2) = Cos (-30/2) = Cos (-15) = Sin (-75) = -0.7596.
¤ Tan (x/2) = Tan (-30/2) = Tan (-15) = -0.6502/-0.7596 = 0.8559.(Tan = Sin/Cos).
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