Math, asked by ashikaushik9494, 1 year ago

Find the value of sin(x/2),cos(x/2) and tan(x/2). if sinx=-1/2 in 3rd quadrant

Answers

Answered by BKGGSS
5
Hello!
Here is your answer

Given

Sin x lies in the third quadrant .

In the third quadrant of the graph the values of X and Y are negative.

Sin x = -1/2

Therefore the value of x is -30

(To know more about trigonometric ratios and values read the table)

¤ Sin (x/2) = Sin (-30/2) = Sin (-15) which is nearly equal to -0.6502.

¤ Cos (x/2) = Cos (-30/2) = Cos (-15) = Sin (-75) = -0.7596.

¤ Tan (x/2) = Tan (-30/2) = Tan (-15) = -0.6502/-0.7596 = 0.8559.(Tan = Sin/Cos).
Answered by anitishram
0

Hello!

Here is your answer

Given

Sin x lies in the third quadrant .

In the third quadrant of the graph the values of X and Y are negative.

Sin x = -1/2

Therefore the value of x is -30

(To know more about trigonometric ratios and values read the table)

¤ Sin (x/2) = Sin (-30/2) = Sin (-15) which is nearly equal to -0.6502.

¤ Cos (x/2) = Cos (-30/2) = Cos (-15) = Sin (-75) = -0.7596.

¤ Tan (x/2) = Tan (-30/2) = Tan (-15) = -0.6502/-0.7596 = 0.8559.(Tan = Sin/Cos).

Similar questions