Math, asked by meena95, 11 months ago

find the value of sin15 degree​

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Answered by Martin84
4

Answer:

 \frac{  \sqrt{3} - 1 }{2 \sqrt{2} }

Step-by-step explanation:

Sin(45 - 30)= sin45cos30 - cos45sin30

sin15 =

 \frac{ \sqrt{3} }{2 \sqrt{2} }  -  \frac{1}{2 \sqrt{2} }  \\  \sin(45)  =  \frac{ \sqrt{3} - 1 }{2 \sqrt{2} }

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