Find the value of sin15° by using sin (A-B)= sinAcosB-cosAsinB
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sin15° = sin(45°-30)
=sin45°cos30° - sin30°cos45°
=(1/√2)×(√3/2) - (1/2)×(1/√2)
=√3/(2√2) - 1/(2√2)
=(√3-1)/(2√2)
=sin45°cos30° - sin30°cos45°
=(1/√2)×(√3/2) - (1/2)×(1/√2)
=√3/(2√2) - 1/(2√2)
=(√3-1)/(2√2)
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