Question

find the value of sin² n/6 + cos² n/3 -tan² n/4​

Answer 1

Answer:

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Step-by-step explanation:

Sin^2(π/6)= cos^2(π/3)= 1/2

Tan(π/4)= 1

Therefore (1/2)^2 + (1/2)^2 - (1)^2

= 1/4 + 1/4 - 1

=1/2 - 1

= -1/2.