find the value of sin²30°+ cos²45° +cos² 30°
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Step-by-step explanation:
sin²30°+ cos²45° +cos² 30°
=1+(1/√2)²(because sin²x+cos²x=1)
=3/2
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sin²30= (1/2)²
cos²45°= (1/√2)²
cos² 30°= (√3/2)²
∴ sin²30°+ cos²45° +cos² 30°=(1/2)²+(1/√2)²+ (√3/2)²
⇒1/4+1/2+3/4
⇒3/2
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