find the value of sin²5+sin²10+sin²80+sin85
Answers
Answered by
0
Answer:
0
Step-by-step explanation:
(sin^5+sin^85)+(sin^10+sin^80)
The important thing is must be the sum is 90°
so finally
(sin^90) (sin^90)=0
Answered by
1
Answer:
Step-by-step explanation:
We have Sin.2 5+ Sin2 10 + Sin2 80 + Sin2 85.
Now Sin square5 and Sin square10 can be written as
Sin square(90-85)+ Sinsquare(90-80) + Sin square80+ Sin square85.
= Cos square85+ Cos square80+ Sin square80+ Sin square85
=Sin square85+ Cos square85+ Sin square80 + Cos square80.
=1+1 , Since(Sin square theta+Cos square theta=1)
=2 Answer.
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