Math, asked by singhbalwan5487, 6 months ago

find the value of sin²5+sin²10+sin²80+sin85

Answers

Answered by vamsip618
0

Answer:

0

Step-by-step explanation:

(sin^5+sin^85)+(sin^10+sin^80)

The important thing is must be the sum is 90°

so finally

(sin^90) (sin^90)=0

Answered by mohdasim777777777
1

Answer:

Step-by-step explanation:

We have Sin.2 5+ Sin2 10 + Sin2 80 + Sin2 85.

Now Sin square5 and Sin square10 can be written as

Sin square(90-85)+ Sinsquare(90-80) + Sin square80+ Sin square85.

= Cos square85+ Cos square80+ Sin square80+ Sin square85

=Sin square85+ Cos square85+ Sin square80 + Cos square80.

=1+1 , Since(Sin square theta+Cos square theta=1)

=2 Answer.

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