find the value of sin2A when tan A=16/63
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sin2a = 2sinAcosA
tana= sina/cosa
or tana= p/b = 16/63
so we get p =16 b= 63
we need to find the third side h so we use pythagorous theorem
c= √p²+b²
c= √16²+63 ²= √4225 = 65
so we got hypotaneious side dude
now
sina = p/h which means
sina = 16/65
and cosa= b/h which means
cosa = 63/65
now we need to calculate sin2a
sin2a = 2sinacosa
now we can directly put our values
sin2a = 2×16/65 ×63/65 = 0.47 approx dude have any doubt ask in comment box
sin 2a = 0.47
tana= sina/cosa
or tana= p/b = 16/63
so we get p =16 b= 63
we need to find the third side h so we use pythagorous theorem
c= √p²+b²
c= √16²+63 ²= √4225 = 65
so we got hypotaneious side dude
now
sina = p/h which means
sina = 16/65
and cosa= b/h which means
cosa = 63/65
now we need to calculate sin2a
sin2a = 2sinacosa
now we can directly put our values
sin2a = 2×16/65 ×63/65 = 0.47 approx dude have any doubt ask in comment box
sin 2a = 0.47
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