Math, asked by soungert, 4 months ago

find the value of sin30 - cot 45​

Answers

Answered by Mɪʀᴀᴄʟᴇʀʙ
21

\LARGE{\rm{\underline{\underline{Answer:-}}}}

sin 30° - cot 45°

= \dfrac{1}{2} - 1

= \dfrac{1 - 1\times 2}{2}

= \dfrac{1 - 2}{2}

= \dfrac{-1}{2}

Or

= - 0.5

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▪︎ Trigonometric Table:-

\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}

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Answered by Itsvaishu366
0

Answer:

sin 30° - cot 45°

= \dfrac{1}{2}21 - 1

= \dfrac{1 - 1\times 2}{2}21−1×2

= \dfrac{1 - 2}{2}21−2

= \dfrac{-1}{2}2−1

Or

= - 0.5

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