Question

find the value of sin330degree×sincos 210+ cos210×sin300degree​

Answer 1

Answer:

sin330=-sin30=-(1/2)

cos120=-cos60=-(1/2)

cos210=-cos30=[-√(3)/2]

sin300=-sin60=[-√(3)/2]

Step-by-step explanation:

putting these values in given equation =sin330×cos120+cos210×sin300=[(-1/2)(-1/2)]+[(-√(3)/2)(-√(3)/2)]

1/4+3/4=1