find the value of sin36degree/cos54degree_tan89degree/cot1degree
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Answer:
we know that sin(90-thita)=cos(thita)
and tan(90-thita)=cot(thita)
so cos54/cos54-cot1/cot1= 1-1=0
so sin36degree/cos54degree_tan89degree/cot1degree= 0
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