find the value of (sin45°+cos45°)
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Answer:
Find the value of (sin45°+cos45°)
Step-by-step explanation:
We know, sin θ = cos (90° - θ)
sin45° = cos ( 90° - 45°)
sin45° = cos 45°
By substituting the value, we get
sin45°+cos45° = cos45°+cos45°
=> 2cos45°
=> 2 X 1/√2 (cos45° = 1/√2)
=> 2/√2
OR
sin45°+cos45°
=> 1/√2 + 1/√2 ( cos45° = 1/√2 and sin45° = 1/√2)
=> 2/√2
Hope this helps you!
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