Math, asked by kamabbas17, 22 days ago

find the value of (sin45°+cos45°)​

Answers

Answered by mukherjeeaanish
0

Answer:

Find the value of (sin45°+cos45°)​

Step-by-step explanation:

We know, sin θ = cos (90° - θ)

sin45° = cos ( 90° - 45°)

sin45° = cos 45°

By substituting the value, we get

sin45°+cos45° =  cos45°+cos45°

=> 2cos45°

=> 2 X 1/√2 (cos45° = 1/√2)

=> 2/√2

OR

sin45°+cos45°

=> 1/√2 + 1/√2 ( cos45° = 1/√2 and sin45° = 1/√2)

=> 2/√2

Hope this helps you!

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