find the value of sin50+sin40 /sin70
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How can you prove that sin 10° sin 30° sin 50° sin 70° = 1/16?
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How can you prove that sin 10° sin 30° sin 50° sin 70° = 1/16?
sin10°=sin(90–80)°=cos80°
sin50°=sin(90–40)°=cos40°
sin70°=sin(90–20)°=cos20°
∴sin10°sin30°sin50°sin70°=cos80°sin30°=12cos40°cos20°
=12⋅cos20°cos40°cos80°=14sin20°⋅(2sin20°cos20°)cos40°cos80°
=18sin20°⋅(2sin40°cos40°)cos80°
=116sin20°⋅(2sin80°cos80°)
=116sin20°⋅(sin160°)=116sin20°⋅(sin(180−20°))
=116sin20°⋅sin20°=116
sin10°sin30°sin50°sin70°
⟹cos80°cos60°cos40°cos20°
⟹12(cos20°cos40°cos80°)
⟹12(2sin20°cos20°)cos40°cos80°2sin20°
⟹14(2sin40°cos40°)cos80°2sin20°
⟹182sin80°cos80°2sin20°
⟹116sin160°sin20°
sin(180°−θ)=sinθ
⟹sin10°sin30°sin50°sin70°=116
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