Question

Find the value of sin60°geometerically

Answer 1

hey here is your answer i hope its help you

Answer 2

firstly u draw an equilateral triangle

ABC in which Draw a perpendicular AD .

BD = a and DC = a and AB = 2a.

Now in ∆ABD

AB^2 = Ad^2 + BD ^ 2

( 2a )^ 2 = AD ^ 2+ a ^2

4a^2 - a ^2 = AD ^2

3a ^2 = AD^2

√3a = AD

Then ,

sin 60= p/h

= √3a/ 2a

= √3/ 2

since , Sin60 = √3/2

hence proved