CBSE BOARD X, asked by bindujayant, 10 months ago

Find the value of sin75 using sin(A+B)= SinACosB+ CosASinB

Answers

Answered by Preeti2607
1

sin75=sin(30+45)

=sin30cos45+cos30+sin45

=1/2.1/√2+√3/2+1/√2

=1/2√2+√3/2√2

=1+√3/2√2

Answered by ankurkumar75572
1

sin75= sin(45 + 30)

= sin45cos30 + cos45sin30

= 1√2 * √3/2 + 1/√2 * 1/2

= √3/2√2 + 1/2√2

= √3 + 1/2√2

=

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