Math, asked by niki8394, 1 year ago

Find the value of sinx, if 6cos²x = 4×1/2?​

Answers

Answered by siddharth19402
0

cosx=

 +  - (1  \div  \sqrt{3} )

sinx=

 \sqrt{1 -  {cos}^{2}x }

sinx=

 \sqrt{2 \div 3}


niki8394: ???
siddharth19402: cmon cant u solve the eqn
niki8394: the answer should be 1/2
siddharth19402: then u have written incorrect question
niki8394: no it is correct
siddharth19402: i have done absolutely correct
niki8394: nooo
niki8394: nooo
siddharth19402: ask anyone if i m wrong
siddharth19402: tell me my mistake then
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