Math, asked by niki8394, 11 months ago

Find the value of sinx, if 6cos²x = 4×1/2?

Answers

Answered by siddharth19402

0

cosx=

$+ - (1 \div \sqrt{3} )$

sinx=

$\sqrt{1 - {cos}^{2}x }$

sinx=

$\sqrt{2 \div 3}$

niki8394: ???

siddharth19402: cmon cant u solve the eqn

niki8394: the answer should be 1/2

siddharth19402: then u have written incorrect question

niki8394: no it is correct

siddharth19402: i have done absolutely correct

niki8394: nooo

niki8394: nooo

siddharth19402: ask anyone if i m wrong

siddharth19402: tell me my mistake then

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