Question

Find the value of small p if the quadratic polynomial p(x) =x^2+8x+p has zeroes whose difference is 4.

Answer 1

Hey there! ^_^
Praneeth from Brainly.in here to help!


Given polynomial
➫ p(x) =x^2+8x+p
===================================✦ In general, for a quadratic polynomial rx²+px+q with roots a,b


here sum of roots =a+b=-p/r
product of roots =ab =q/r
===================================
✦ Let the first root be x
✦ then second root be x-4

➫ Sum of roots =x+(x-4)=2x-4
➫ But according to formula
➫ Sum of roots =-8/1

➫ -8=2x-4
➫2x =-8+4
➫ 2x=-4
➫ x=-2

✦Therefore roots are -2,-6
➫Products of roots = -2*-6=12
➫ But according to formula,
➫ Product of roots =p/1=p

➫ p=12
✦Therefore value of p=12


==========================================

✦ Quadratic polynomial =p(x)=x^2+8x+12
✦Value of p=12
✦Roots of p(x) are -2,-6

hope helped!

-Regards,
Praneeth,
✪Brainly benefactor✪

Answer 2

Answer:Find the value of small p if the quadratic polynomial p(x) =x^2+8x+p has zeroes whose difference is 4.

Step-by-step explanation: