Math, asked by AlbertEinsteinsDad, 9 months ago

Find the value of smallest positive integers 'n' for which 432 × n is a perfect cube

Answers

Answered by nizamouddinshaikh
0

Answer:333

Step-by-step explanation:

Answered by kingofself
2

Answer:

The value of smallest positive integer for the given is 12.

Step-by-step explanation:

Given:

Find the value of smallest positive integers 'n' for which 432 \times n is a perfect cube

Solution:

432 \times n = x \times x \times x

n is a single digit which can be from 1 to 9

n = 1, we get 432,

n = 2 we get 864

432, 864, 1296, 1728, …..

Consider the cube root of the numbers,

Hence 3 \sqrt{1728} = 12

Result:

The value of smallest positive integer for the given is 12.

Learn more about smallest positive integers:

Q: Find the smallest positive integer value of n for which (1+i)^n/(1-i)^n-2 is a real number

Link: https://brainly.in/question/5334755

Q: What is the difference between the smallest positive integer and the largest negative integer

Link: https://brainly.in/question/1142259

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