Question

Find the value of so that the quadratic equation (5−6)=0 has two equal roots.

Answer 1

Step-by-step explanation:

Given,

kx(x-2)+6=0

kx

2

-kx+6=0

Since the roots are equal

b

2

=49c

(-2k)

2

=4(k) (6)

4k

2

=4k(6)

k =6

Answer 2

Given equation mx(x−7)+49=0 if given equation has equal roots then discriminant 0=b

2

−4ac=0.

m

a

x

2

−

7

a

mx+

49

c

=0

(7m)

2

−4×m×49=0

(7m)

2

=196 m

49m

2

−196 m=0

49m(m−4)=0

m=0,4 but m



=0

∴m=4