Find the value of so that the quadratic equation (5 − 6) = 0 has two
equal root
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Step-by-step explanation:
ko
px2-3px+9=0
a=p , b=-3p , c=9
b2-4ac= (-3p)2-4(p)(9)
=9p2-36p
for having equal roots
b2-4ac = 9p2-36p = 0
9p2-36p = 0
9p(p-4) = 0
9p=0 (or) p-4=0
p=0(rejected) or p=4
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