find the value of, sqare root of 1 mines sin square 100 degrees. sec 100degrees
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Step-by-step explanation:
100° lies in second quadrant(Q2)
In Q2 only sin and csc are +ve.
Rest all trignometric ratios are negative.
√(1-sin²100°)×sec100°
√cos²100°×sec100°
-cos100°×sec100°
-1
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