Question

Find the value of square of (x-3y+2z)
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Answer 1

(x-3y+2x)²

= x²+(-3y)²+(2x)²+2{(x)(-3y)+(-3y)(2z)+(2z)(x)}

= x²+9y²+4x²+2{-3xy-6yz+2zx}

= x²+9y²+4x²-6xy-12yz+4zx

Using identity,(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

Hope it helps....

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Answer 2

Step-by-step explanation:

(x-3y+2z)×(x-3y+2z)

x^2-3xy+2xz-3xy+9y^2-6yz+2xz-6yz+4z^2

x^2-6xy+4xz+9y^2-12yz+z^2