Question

find the value of square root 0.31428 correct to three decimals places
​

Answer 1

Answer: square root of 0.31428=0.56060681408

                                                       =0.560

                                                       =0.56

Step-by-step explanation:

Hope it helps

Please mark the brainliest

Answer 2

Answer:

hilu ❤️

Step-by-step explanation:

How do you find the value of the square root of 3.1428 and 0.31428, correct to three decimal places?

31428/10^4 and 314280/10^6

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too big

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integer

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integerNewton’s method for the square root of N function can be reduced to iterating

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integerNewton’s method for the square root of N function can be reduced to iteratingx = 0.5(x +N/x)

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integerNewton’s method for the square root of N function can be reduced to iteratingx = 0.5(x +N/x)Iteration 1: x = 0.5(177 + 31428/177) = 177.27966

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integerNewton’s method for the square root of N function can be reduced to iteratingx = 0.5(x +N/x)Iteration 1: x = 0.5(177 + 31428/177) = 177.27966and using square root key, actual value is 177.27944 so the first iteration is good enough. Remember the square root of the 10^4 denominator. The answer to three decimals is 177.28/100 and rounded as required, 1.773.

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integerNewton’s method for the square root of N function can be reduced to iteratingx = 0.5(x +N/x)Iteration 1: x = 0.5(177 + 31428/177) = 177.27966and using square root key, actual value is 177.27944 so the first iteration is good enough. Remember the square root of the 10^4 denominator. The answer to three decimals is 177.28/100 and rounded as required, 1.773.In the same manner for 314580,

31428/10^4 and 314280/10^6Now focus on a rough square root estimate for 31428100^2 = 10000, way too small200^2 = 40000, somewhat too big180^2 = 32400, just a bit too bigContinuing in this manner, 177^2 = 31329 and is the closest integerNewton’s method for the square root of N function can be reduced to iteratingx = 0.5(x +N/x)Iteration 1: x = 0.5(177 + 31428/177) = 177.27966and using square root key, actual value is 177.27944 so the first iteration is good enough. Remember the square root of the 10^4 denominator. The answer to three decimals is 177.28/100 and rounded as required, 1.773.In the same manner for 314580,500² = 250 000, 600² = 360 000, continuing, 560² = 313 600

I 1: x =0.5(560 + 314280/560) = 560.607

1: x =0.5(560 + 314280/560) = 560.607Iteration 2 gives 560.606814, so we have more digits than we need.

1: x =0.5(560 + 314280/560) = 560.607Iteration 2 gives 560.606814, so we have more digits than we need.Remember to divide by 1000, 0.56061, or to 3 digits,. 0.561.